Energy in simple harmonic motion, kinetic and potential energies, simple pendulum and its time period - One Line Questions

1. The maximum kinetic energy of a particle in SHM is given by: (1/2)mω^2A^2
2. The maximum potential energy of a particle in SHM is equal to: (1/2)kA^2
3. For a particle executing SHM, the velocity is v = ω√(A^2 - x^2). The kinetic energy is KE = (1/2)mv^2. What is the expression for KE in terms of displacement x? (1/2)mω^2(A^2 - x^2)
4. What is the angular frequency (ω) of a simple pendulum of length L? √(g/L)
5. If the amplitude of oscillation of a system in SHM is A, the maximum displacement from the mean position is: A
6. A simple pendulum has a time period of 2 seconds. If its length is increased by 1 meter, its time period becomes 3 seconds. The original length of the pendulum is approximately: 0.75 m
7. If the time period of a simple pendulum is T, and its length is increased by 24 cm, its time period becomes T + 1 second. The original length of the pendulum is: 2 m
8. When the displacement of a particle in SHM is equal to half of its amplitude, the ratio of its kinetic energy to its potential energy is: 3:1
9. What is the time period of a simple pendulum of length 1 meter on the surface of the Earth (g ≈ 9.8 m/s²)? 2.0 s
10. For a simple pendulum, the time period (T) is approximately 2.0 seconds. If the length of the pendulum is increased by a factor of 4, what will be the new time period? 4.0 seconds
11. A simple pendulum has a time period T. If its length is increased such that its time period becomes 2T, what is the factor by which the length has increased? 4
12. A simple pendulum has a time period of 4 seconds. If its length is increased by 3 times, what will be the new time period? 8 seconds
13. A body is performing SHM. Its total energy is E. At a displacement x = A/2 from the mean position, what is its kinetic energy? 3E/4
14. A simple pendulum's length is increased by 21 cm, and its time period increases from 2 seconds to 2.2 seconds. The original length of the pendulum is: 90 cm
15. The total energy of a particle in SHM is proportional to: Square of amplitude
16. In SHM, the total energy is the sum of kinetic and potential energies. At any point, E = KE + PE. Which statement is always true about E? E is constant
17. The total energy of a simple harmonic oscillator is E. What is the kinetic energy when the displacement is A/2? 3E/4
18. The energy in SHM is continuously converted between kinetic and potential forms. At any instant, the total energy is: The sum of kinetic and potential energy
19. For a particle in SHM, the kinetic energy is maximum when the velocity is maximum. This occurs at: Mean position
20. What is the unit of angular frequency (ω) for a simple pendulum? Radians per second (rad/s)
21. If a pendulum clock is taken to a place of higher altitude, its time period will: Increase
22. The time period of a simple pendulum is T. If it is made to oscillate in a liquid of negligible viscosity, its time period will: Remain the same
23. If the mass of the bob of a simple pendulum is increased, what happens to its time period? Remains the same
24. Which statement is correct regarding the total energy of a simple harmonic oscillator? It is constant throughout the motion.
25. If the amplitude of a SHM is doubled, how does the total energy of the system change? It quadruples
26. For a simple pendulum, if the length is halved, how does the time period change? It decreases by a factor of √2
27. If a simple pendulum is taken to the Moon where the acceleration due to gravity is approximately 1/6th of that on Earth, how will its time period change? It will increase
28. In Simple Harmonic Motion (SHM), what is the relationship between kinetic energy (KE) and potential energy (PE) at the extreme positions of the oscillation? KE is zero, PE is maximum
29. When an object is at the mean position in SHM, what is the state of its kinetic energy and potential energy? KE is maximum, PE is zero
30. When the speed of a particle in SHM is zero, its energy is purely: Potential
31. For a simple pendulum, the time period is directly proportional to: Square root of length
32. Which of the following factors does NOT affect the time period of a simple pendulum? Mass of the bob
33. The potential energy of a particle executing SHM is given by U = (1/2)kx^2, where k is the spring constant and x is the displacement from the mean position. What is the nature of this potential energy? Quadratic
34. The time period of a simple pendulum depends on which of the following quantities? Length of the string and acceleration due to gravity
35. When is the potential energy of a particle in SHM equal to its kinetic energy? At positions where the displacement is ± A/√2
36. If the frequency of a SHM is f, what is its time period T? T = 1/f
37. What is the formula for the time period (T) of a simple pendulum of length L in a location with acceleration due to gravity g? T = 2π * sqrt(L/g)
38. For a simple pendulum, the time period T is given by T = 2π√(L/g). If g is doubled, the new time period T' will be: T/√2
39. The time period of a simple pendulum is T. If the mass of the bob is doubled, the new time period will be: T
40. If the length of a simple pendulum is L and its time period is T, then a pendulum of length L/2 will have a time period of: T/√2
41. The kinetic energy of a particle in SHM is maximum when the particle is at: The mean position
42. The potential energy of a particle in SHM is zero at: The mean position
43. The kinetic energy of a particle in SHM is zero at: The extreme positions
44. The potential energy of a particle executing SHM is maximum when the particle is at: The extreme position
45. The total energy of a system in SHM is conserved if: There are no non-conservative forces acting on the system
46. For a system undergoing SHM, which of the following statements about the total mechanical energy is correct? Total energy is proportional to the amplitude squared
47. In SHM, when the displacement is x, the potential energy is proportional to: x^2
48. In SHM, the average kinetic energy over one complete oscillation is equal to: Half of the total energy
49. In SHM, the average potential energy over one complete oscillation is equal to: Half of the total energy
50. The potential energy of a particle in SHM is maximum when the displacement is: Amplitude