Energy in simple harmonic motion, kinetic and potential energies, simple pendulum and its time period - One Line Questions
1.
The maximum kinetic energy of a particle in SHM is given by: —
(1/2)mω^2A^2
2.
The maximum potential energy of a particle in SHM is equal to: —
(1/2)kA^2
3.
For a particle executing SHM, the velocity is v = ω√(A^2 - x^2). The kinetic energy is KE = (1/2)mv^2. What is the expression for KE in terms of displacement x? —
(1/2)mω^2(A^2 - x^2)
4.
What is the angular frequency (ω) of a simple pendulum of length L? —
√(g/L)
5.
If the amplitude of oscillation of a system in SHM is A, the maximum displacement from the mean position is: —
A
6.
A simple pendulum has a time period of 2 seconds. If its length is increased by 1 meter, its time period becomes 3 seconds. The original length of the pendulum is approximately: —
0.75 m
7.
If the time period of a simple pendulum is T, and its length is increased by 24 cm, its time period becomes T + 1 second. The original length of the pendulum is: —
2 m
8.
When the displacement of a particle in SHM is equal to half of its amplitude, the ratio of its kinetic energy to its potential energy is: —
3:1
9.
What is the time period of a simple pendulum of length 1 meter on the surface of the Earth (g ≈ 9.8 m/s²)? —
2.0 s
10.
For a simple pendulum, the time period (T) is approximately 2.0 seconds. If the length of the pendulum is increased by a factor of 4, what will be the new time period? —
4.0 seconds
11.
A simple pendulum has a time period T. If its length is increased such that its time period becomes 2T, what is the factor by which the length has increased? —
4
12.
A simple pendulum has a time period of 4 seconds. If its length is increased by 3 times, what will be the new time period? —
8 seconds
13.
A body is performing SHM. Its total energy is E. At a displacement x = A/2 from the mean position, what is its kinetic energy? —
3E/4
14.
A simple pendulum's length is increased by 21 cm, and its time period increases from 2 seconds to 2.2 seconds. The original length of the pendulum is: —
90 cm
15.
The total energy of a particle in SHM is proportional to: —
Square of amplitude
16.
In SHM, the total energy is the sum of kinetic and potential energies. At any point, E = KE + PE. Which statement is always true about E? —
E is constant
17.
The total energy of a simple harmonic oscillator is E. What is the kinetic energy when the displacement is A/2? —
3E/4
18.
The energy in SHM is continuously converted between kinetic and potential forms. At any instant, the total energy is: —
The sum of kinetic and potential energy
19.
For a particle in SHM, the kinetic energy is maximum when the velocity is maximum. This occurs at: —
Mean position
20.
What is the unit of angular frequency (ω) for a simple pendulum? —
Radians per second (rad/s)
21.
If a pendulum clock is taken to a place of higher altitude, its time period will: —
Increase
22.
The time period of a simple pendulum is T. If it is made to oscillate in a liquid of negligible viscosity, its time period will: —
Remain the same
23.
If the mass of the bob of a simple pendulum is increased, what happens to its time period? —
Remains the same
24.
Which statement is correct regarding the total energy of a simple harmonic oscillator? —
It is constant throughout the motion.
25.
If the amplitude of a SHM is doubled, how does the total energy of the system change? —
It quadruples
26.
For a simple pendulum, if the length is halved, how does the time period change? —
It decreases by a factor of √2
27.
If a simple pendulum is taken to the Moon where the acceleration due to gravity is approximately 1/6th of that on Earth, how will its time period change? —
It will increase
28.
In Simple Harmonic Motion (SHM), what is the relationship between kinetic energy (KE) and potential energy (PE) at the extreme positions of the oscillation? —
KE is zero, PE is maximum
29.
When an object is at the mean position in SHM, what is the state of its kinetic energy and potential energy? —
KE is maximum, PE is zero
30.
When the speed of a particle in SHM is zero, its energy is purely: —
Potential
31.
For a simple pendulum, the time period is directly proportional to: —
Square root of length
32.
Which of the following factors does NOT affect the time period of a simple pendulum? —
Mass of the bob
33.
The potential energy of a particle executing SHM is given by U = (1/2)kx^2, where k is the spring constant and x is the displacement from the mean position. What is the nature of this potential energy? —
Quadratic
34.
The time period of a simple pendulum depends on which of the following quantities? —
Length of the string and acceleration due to gravity
35.
When is the potential energy of a particle in SHM equal to its kinetic energy? —
At positions where the displacement is ± A/√2
36.
If the frequency of a SHM is f, what is its time period T? —
T = 1/f
37.
What is the formula for the time period (T) of a simple pendulum of length L in a location with acceleration due to gravity g? —
T = 2π * sqrt(L/g)
38.
For a simple pendulum, the time period T is given by T = 2π√(L/g). If g is doubled, the new time period T' will be: —
T/√2
39.
The time period of a simple pendulum is T. If the mass of the bob is doubled, the new time period will be: —
T
40.
If the length of a simple pendulum is L and its time period is T, then a pendulum of length L/2 will have a time period of: —
T/√2
41.
The kinetic energy of a particle in SHM is maximum when the particle is at: —
The mean position
42.
The potential energy of a particle in SHM is zero at: —
The mean position
43.
The kinetic energy of a particle in SHM is zero at: —
The extreme positions
44.
The potential energy of a particle executing SHM is maximum when the particle is at: —
The extreme position
45.
The total energy of a system in SHM is conserved if: —
There are no non-conservative forces acting on the system
46.
For a system undergoing SHM, which of the following statements about the total mechanical energy is correct? —
Total energy is proportional to the amplitude squared
47.
In SHM, when the displacement is x, the potential energy is proportional to: —
x^2
48.
In SHM, the average kinetic energy over one complete oscillation is equal to: —
Half of the total energy
49.
In SHM, the average potential energy over one complete oscillation is equal to: —
Half of the total energy
50.
The potential energy of a particle in SHM is maximum when the displacement is: —
Amplitude