Universal law of gravitation, acceleration due to gravity and its variation with altitude and depth - One Line Questions
1.
If an object weighs 100 N on Earth's surface, its mass is approximately: —
10.2 kg
2.
If the Earth's mass increases by 10% and its radius decreases by 5%, what is the approximate percentage change in acceleration due to gravity on its surface? —
20% increase
3.
What is the approximate value of the universal gravitational constant G? —
6.67 x 10^-11 N m^2 / kg^2
4.
The acceleration due to gravity 'g' on the surface of the Earth is approximately: —
9.8 m/s^2
5.
The formula g' = g (R / (R + h))^2 for acceleration due to gravity at height 'h' is valid for: —
All values of h
6.
The acceleration due to gravity at a depth 'd' below the Earth's surface is given by g'' = g (1 - d/R), for: —
d << R
7.
The acceleration due to gravity at a height 'h' above the Earth's surface is given by g' = g (1 - 2h/R), for: —
h << R
8.
The variation in acceleration due to gravity with altitude is due to: —
Change in distance from the Earth's center
9.
The variation in acceleration due to gravity with depth is due to: —
Change in the mass of the Earth above the point
10.
The universal law of gravitation is a statement about the force between: —
Any two objects with mass
11.
The acceleration due to gravity at height 'h' above the Earth (radius R) is g' = g (R/(R+h))^2. For very large heights (h >> R), g' approaches: —
Zero
12.
What is the formula for acceleration due to gravity at a height 'h' above the Earth's surface, where R is the radius of the Earth? —
g' = g (R / (R + h))^2
13.
What is the formula for acceleration due to gravity at a depth 'd' below the Earth's surface? —
g'' = g (R - d) / R
14.
The acceleration due to gravity at a depth 'd' below the Earth's surface is g'' = g(1 - d/R). If d = R/2, then g'' is: —
g/2
15.
If an object is brought from the surface of the Earth to a depth equal to the Earth's radius (i.e., the center), its acceleration due to gravity changes from g to: —
0
16.
The formula g'' = g (1 - d/R) for acceleration due to gravity at depth 'd' implies that: —
Gravity decreases linearly with depth
17.
The formula g' = g (1 - 2h/R) is an approximation for acceleration due to gravity at height 'h'. This approximation is valid when: —
h is very small compared to R
18.
If the Earth were to rotate faster, the apparent acceleration due to gravity at the equator would: —
Decrease
19.
As we go up from the surface of the Earth to a great height, the acceleration due to gravity: —
Decreases
20.
As we go down from the surface of the Earth into a mine, the acceleration due to gravity: —
Decreases
21.
As an object moves away from the Earth's center, its weight: —
Decreases
22.
Which of the following statements is correct regarding the acceleration due to gravity? —
It is minimum at the equator and maximum at the poles
23.
If an object is taken from the surface of the Earth to a height equal to the Earth's radius, by what factor does the acceleration due to gravity change? —
It becomes 1/4th
24.
The acceleration due to gravity on the surface of a planet is inversely proportional to: —
The square of its radius
25.
The weight of an object is: —
Its mass multiplied by acceleration due to gravity
26.
The acceleration due to gravity on the surface of a planet is directly proportional to: —
Its mass
27.
If the Earth's radius were R and its mass M, the acceleration due to gravity on its surface is proportional to: —
M/R^2
28.
The gravitational force exerted by the Earth on an object is its: —
Weight
29.
Which of the following factors does NOT affect the acceleration due to gravity on the surface of a planet? —
Mass of the object placed on the planet
30.
At the center of the Earth (d=R), the acceleration due to gravity is: —
Minimum (zero)
31.
The gravitational constant 'G' has the unit: —
N m^2 / kg^2
32.
If the mass of the Earth were doubled, keeping its radius constant, the acceleration due to gravity on its surface would: —
Become double
33.
If the radius of the Earth were halved, keeping its mass constant, the acceleration due to gravity on its surface would: —
Become four times
34.
The gravitational force between two objects is always: —
Attractive
35.
Which of the following is a consequence of the variation of acceleration due to gravity with altitude? —
Objects weigh less at higher altitudes
36.
The universal law of gravitation implies that every particle of matter attracts every other particle with a force: —
That is proportional to the product of their masses and inversely proportional to the square of the distance between them
37.
The term 'acceleration due to gravity' usually refers to its value at: —
The Earth's surface
38.
The formula g'' = g (1 - d/R) for acceleration due to gravity at depth 'd' is derived assuming: —
The Earth has uniform density throughout
39.
The variation in 'g' with latitude is mainly due to: —
The Earth's rotation
40.
The value of acceleration due to gravity is approximately 9.8 m/s^2 at: —
Sea level
41.
The acceleration due to gravity 'g' depends on: —
The mass of the planet
42.
The acceleration due to gravity on the Moon is approximately 1/6th of that on Earth. This is primarily because: —
The Moon has a smaller mass than Earth
43.
The effect of Earth's rotation on acceleration due to gravity is most pronounced at: —
The equator
44.
Newton's universal law of gravitation states that the force of attraction between two point masses is inversely proportional to: —
The square of the distance between them
45.
The decrease in acceleration due to gravity with depth is due to: —
The reduction in the mass of the Earth above the point
46.
According to Newton's universal law of gravitation, the force of attraction between two point masses is directly proportional to: —
The product of their masses
47.
The reason why astronauts feel weightless in orbit is: —
They are in a state of continuous free fall
48.
The acceleration due to gravity decreases with altitude because the distance from the center of the Earth increases, and the gravitational force is proportional to the inverse square of the distance. This statement is: —
True for all altitudes
49.
What is the value of acceleration due to gravity at the Earth's center, assuming uniform density? —
Zero
50.
When an object falls freely under gravity, its acceleration is: —
Equal to the acceleration due to gravity at that location